0=4.9x^2+34x

Solution for 0=4.9x^2+34x equation:

0=4.9x^2+34x

We move all terms to the left:

0-(4.9x^2+34x)=0

We add all the numbers together, and all the variables

-(4.9x^2+34x)=0

We get rid of parentheses

-4.9x^2-34x=0

a = -4.9; b = -34; c = 0;
Δ = b2-4ac
Δ = -342-4·(-4.9)·0
Δ = 1156
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1156}=34$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-34)-34}{2*-4.9}=\frac{0}{-9.8}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-34)+34}{2*-4.9}=\frac{68}{-9.8}
=-6+1/1.0652173913043
$